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View Full Version : Host-Magno [ Read More ] Cheep Hosting



RedMaggot
21-12-2004, 10:12 PM
Hey,
im Alex the owner of Host-Magno that opned to day and would like to take one min of ur time to talk to you about it,
its cheep and i dont know why loads of host ( Ax eg. ) make you pay so much when i can do better for less,
I will work out the price from what you are looking for.

must have PayPal

Mentor
21-12-2004, 10:46 PM
ok ill looked it up. there not actaly a site there, and from what i see it doenst sound at all relibale. plus its adverting jobs on digiwire forums. Athogh they are very good prices, i have no idea of the hosts spec's, performans, scripting lnangwages supported, terms of servis, etc etc etc.

-JT-
21-12-2004, 11:34 PM
i don't particularly beilive you, bandwoth costs alot of money, so do servers. you stupid koon.

Bukker
22-12-2004, 12:25 AM
we need a site to see prove it is a hosting company must look professional and spell correctly plus .coms are £8 or more

McForesT
22-12-2004, 09:19 AM
sounds like a scam, and btw. ur ping times shows slow connection :x

-JT-
22-12-2004, 11:43 AM
have you seen his site?

Mentor
22-12-2004, 01:49 PM
hes offering jobs on it here http://forums.digiwire.org/index.php?showtopic=866&st=0&p=7603&#entry7603

and the site is here http://www.host-magno.com/

RedMaggot
22-12-2004, 02:01 PM
James - Yes but my mate owns a server and i get it cheep and i rent it
Mentor - Jay is the old owner and my mate tht i rent the server from
James - www.host-magno.com
Mc - its not a scam you can ask Jane the habbo staff as she is thinking about sweing me
Mentor - the Prices have been edited as that was a one day openering thing

McForesT
23-12-2004, 12:52 PM
If this a official company with certicates etc. etc., or just something u just set up, to get some extra moneys for christmas ? :)

RedMaggot
24-12-2004, 11:22 AM
Somthing for me to get more money and all my mates to get hosting,
im not in it like Ax that change high prices i do add like 50p for myself
but not like Ax that add 200 pound =P

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