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BowTies1
21-10-2007, 07:44 PM
Factorise Fully :

7f(squared) g (sqaured) - FG

b) 6m(squared) + 13 m + 5

c) 9p(squared) + 18p - 16

d) 12p(squared) - 3

e) 35 - 2q - q Squared


please help

Nemo
21-10-2007, 07:46 PM
Factorise Fully :

7f(squared) g (sqaured) - FG

b) 6m(squared) + 13 m + 5

c) 9p(squared) + 18p - 16

d) 12p(squared) - 3

e) 35 - 2q - q Squared


please help

c)84p
D)141p

cba to do the others and im not sure if they are right or not ;]

whoooosh
21-10-2007, 07:49 PM
when you say squared
do you mean just the letter squared
or the letter and the number ?

BowTies1
21-10-2007, 07:50 PM
just the letter

Energizer
21-10-2007, 07:51 PM
c)84p
D)141p

cba to do the others and im not sure if they are right or not ;]

they wouldn't be right cos you can't take the 16 away from the 'p''s

Nemo
21-10-2007, 07:53 PM
they wouldn't be right cos you can't take the 16 away from the 'p''s
oh woops i thought it was money LOL

BowTies1
21-10-2007, 07:53 PM
nauht there wrong its facroisation

so its like

2 brackets
( )( ) and they should mutilply out to be the same as what i gave you

Throne Sofa
22-10-2007, 12:01 AM
Do you still need help?
I've been doing this in maths very recently.

1.)
7F2 G2 - FG = FG (7F-G)

2.) 6m2 + 13 m + 5 = M (6M+13+5)

If you need help with the others, just tell me. I don't want to be doing them for a loss cause if you've allready got the answers. :)

BowTies1
22-10-2007, 04:46 PM
number 2 is wrong becuase were looking for 5 and in the brcket it would come out as 5m

jackass
22-10-2007, 04:53 PM
c)84p
D)141p

cba to do the others and im not sure if they are right or not ;]

Wrong. xD


when you say squared
do you mean just the letter squared
or the letter and the number ?

Lol.


they wouldn't be right cos you can't take the 16 away from the 'p''s

Exactly. (:


oh woops i thought it was money LOL

Erm, lol.


Do you still need help?
I've been doing this in maths very recently.

1.)
7F2 G2 - FG = FG (7F-G)

2.) 6m2 + 13 m + 5 = M (6M+13+5)

If you need help with the others, just tell me. I don't want to be doing them for a loss cause if you've allready got the answers. :)

Wrong, because you can't have 5m. (:

BowTies1
22-10-2007, 04:55 PM
bio got any ideas?

jackass
22-10-2007, 04:56 PM
bio got any ideas?

I'll help later, I could do all of them most probaly.

But i'm really busy right now... & I cba. (;

BowTies1
22-10-2007, 05:00 PM
no problem when will youhave some spare time to help ?

Ramones
22-10-2007, 08:21 PM
i'll do no.2 for you because i'm nice

6m(squared) + 13m + 5

=

(2m + 1) (3m + 5)


YOU SHOULD OF RECOGNISED THE QUADRATIC

edit: 3. = (3p+8)(3p-2)

4. = 3(4p-1) i think

5. = (x+5) (x-7)

don't say i never do anything for you.

BowTies1
22-10-2007, 09:29 PM
thanks its allcoming abck to me know youve been some help how cani repay you

Ramones
23-10-2007, 12:16 PM
have my babies.

Edited by ,Jess, (Forum Moderator): Please do not make pointless posts.

Jesus-Egg
25-10-2007, 09:46 PM
a) 7f2g2 +fg
You need to find the common factor between 7f2g2 and fg, which is fg. So you need to take fg out, and you get:
fg(7fg-1)

b) 6m2+13m+5
This is one of the ones that you need to put in 2 sets of brackets. There's either going to be 6m and m, or 2m and 3m to multiply to give 6m2, but you don't know which. You also know the numbers must multiply to give 5, so they must be 1 and 5. All you can do now is trial and error until you get the right answer, which should be (2m+1)(3m+5)

c) 9p2+18p-16
There's going to be either p and 9p, or 3p and 3p, and the number bit could be either 1 and 16, 2 and 8, or 4 and 4, with one positive and one negative, so again all you can really do is trial and error. You should get the answer (3p+8)(3p-2)

d) 12p2-3
You should notice straight away that 3 is a common factor, so you get 3(4p2-1)
If you look at the bit in the brackets, and imagine it says 4P2+0p-1 you know there's going to be 1 and -1, and to get the 0p, you must have 2p and 2p, therefore the final answer is 3(2p+1)(2p-1)

e) 35-2q-q2
Personally, i prefer to write it as -q2-2q+35. You know that there must be q and -q, and to get -2q, there must be 5 and 7, so you get (q+7)(-q+5), which can also be written as (7+q)(5-q) if you prefer it

Hope that helped :)

Throne Sofa
25-10-2007, 10:50 PM
No bio, don't tell me i'm wrong as I never put 5m, so get your facts straight. I did this in class the week before half term, and got a's for it therefore I know for sure I am right in my answers. In factorising you need brackets in your answer.

Jesus-Egg
25-10-2007, 11:07 PM
No bio, don't tell me i'm wrong as I never put 5m, so get your facts straight. I did this in class the week before half term, and got a's for it therefore I know for sure I am right in my answers. In factorising you need brackets in your answer.

what he meant was that if you were to multiply out your answer of m(6m+13+5), you get 6m2+13m+5m, so your answer cannot be right, as it should be 5, not 5m.

Jambe
26-10-2007, 01:52 PM
What type of Factorsing? Factorising is normaly lyke

24p squared - 4p cubed
P4(6p-PPP)

?

SHOKER
26-10-2007, 02:12 PM
where the hell are you gonna use this later in life? schools are bloody ridiculus sometimes

Alkaz
26-10-2007, 02:22 PM
dw lol

le harry
26-10-2007, 02:29 PM
i did factorising ages ago
thats quadratics right?

BowTies1
27-10-2007, 10:10 PM
some of them were quadratics

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